How can I exploit the following code using string format vulnerabilities, Global offset table & GDB?

How can I exploit the following code using string format vulnerabilities, Global offset table & GDB?

The following code should be exploited and I need to exploit it in such a way that it runs my command (l33t) and there should be shellcode and exploit included, so that it runs my command. I believe I need to use GDB and it has something to do with the global offset table and is potentially a string format vulnerability (although I could be wrong). It is the C code shown below.

include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>

int sudoexec(char *command)
{
  FILE *f = NULL;
  char log_entry[64];
  char line[256];

  f = fopen("sudolog", "a");
  if (f == NULL)
    {
      fprintf(stderr, "Can't open sudolog file\n");
      return -1;
    }
  snprintf(log_entry, 64, "%d: %s\n", getuid(), command);
  
  fprintf(f, log_entry, NULL);
  fclose(f);

  f = fopen("sudoers", "r");
  if (f == NULL)
    {
      fprintf(stderr, "Can't open sudoers file\n");
      return -1;
    }

  while(fgets(line, 256, f) != NULL)
    { 
      if (atoi(line) == getuid())
        {
          if (setuid(0) == 0) {
            system(command);
          } else {
            fprintf(stderr, "Setting the UID to root failed: check permissions\n");
          }

          fclose(f);
          return 0;
        }
    }
  fprintf(stderr, "User not listed in the sudoers file\n");
return -1;
}

int main (int argc, char** argv)
{

  if (argv[1] == NULL)
    {
      fprintf(stderr, "Missing args\n");
      return -1;
    }
  
  if (sudoexec(argv[1]) != 0)
    {
      fprintf(stderr, "Cannot execute your command\n");
      return -1;
    }
  return 0;
}

Please share the exploit and shellcode and please explain the procedure used to exploit this code so that it ran my command (l33t).